Interest earned in scheme M =   

P 1 + 20 100 2 - 1 = 11 P 25

Interest earned in scheme N =  

P x k x 2 100 = P k 50

Now, from the given data,

11 P 25 = 2 x P k 50

k = 11

Present Worth

= P 1 + R 100 2

= 169 1 + 4 100 2

= Rs.156.25

C.I.= Rs.[4000*(1+10/100)^2-4000]

 =Rs.840

sum=Rs.(420 * 100)/3*8=Rs.1750

We know the formula for calculating

The compound interest  C = P 1 + r 100 n - 1 where P = amount, r = rate of interest, n = time

Here P = 5000, r1 = 10, r2 = 20

Then  $$\begin{gathered} C = 6500 1 + 10 100 2 x 1 + 20 100 2 - 1 \\ = 6500 x 1856 2500 \\ = 65 x 1856 25 \end{gathered}$$

C = Rs. 4826.

Let 'R%' be the rate of interest

From the given data,

$$\begin{gathered} 2520 2400 = 1 + R 100 4 1 + R 100 3 \\ ? 1 + R 100 = 63 60 \\ ? R = 5 \end{gathered}$$

Hence, the rate of interest R = 5% per annum.

Let Rs. K invested in each scheme

Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%

Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%

Now,

(P x 44/100) - (P x 32.25/100) = 528.75

=> 11.75 P = 52875

=> P = Rs. 4500

Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.

8000 × 33.1% = 2648

Compound Interest for 1 ¹?₂ years when interest is compounded yearly = Rs.(5304 - 5000)

Amount after 1¹?₂ years when interest is compounded half-yearly 


Compound Interest for 1 ¹?₂ years when interest is compounded half-yearly = Rs.(5306.04 - 5000)

Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04

Given compound interest for 3 years = Rs. 1513.2

and simple interest for 5 years = Rs. 2400

Now, we know that  C.I =  P 1 + R 100 n - 1

=> 1513.2 =  P 1 + R 100 3 - 1 ...........(A)

And S.I = PTR/100

=> 2400 = P5R/100 ..................(B)

By solving (A) & (B), we get

R = 5%.

Amount

= Rs.(25000x(1+12/100)³

= Rs.(25000x28/25x28/25x28/25)

= Rs. 35123.20.

C.I = Rs(35123.20 -25000)

= Rs.10123.20