∴ R = | ❨ | 100 x 60 | ❩ | = 10% p.a. |
100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
∴ C.I. |
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= 3972. |
2 | 1 |
2 |
Let the time be n years.
Then, 30000 | ❨ | 1 + | 7 | ❩ | n | = 34347 |
100 |
⟹ | ❨ | 107 | ❩ | n | = | 34347 | = | 11449 | = | ❨ | 107 | ❩ | 2 |
100 | 30000 | 10000 | 100 |
∴ n = 2 years.
[ | 15000 x | ❨ | 1 + | R | ❩ | 2 | - 15000 | ] | - | ❨ | 15000 x R x 2 | ❩ | = 96 | |
100 | 100 |
⟹ 15000 | [ | ❨ | 1 + | R | ❩ | 2 | - 1 - | 2R | ] | = 96 |
100 | 100 |
⟹ 15000 | [ | (100 + R)2 - 10000 - (200 x R) | ] | = 96 |
10000 |
⟹ R2 = | ❨ | 96 x 2 | ❩ | = 64 |
3 |
⟹ R = 8.
∴ Rate = 8%.
C.I. |
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= Rs. 840. |
∴ Sum = Rs. | ❨ | 420 x 100 | ❩ | = Rs. 1750. |
3 x 8 |
C.I. = | [ | x | ❨ | 1 + | 4 | ❩ | 2 | - x | ] | = | ❨ | 676 | x | - x | ❩ | = | 51 | x. |
100 | 625 | 625 |
S.I. = | ❨ | x x 4 x 2 | ❩ | = | 2x | . |
100 | 25 |
∴ | 51x | - | 2x | = 1 |
625 | 25 |
⟹ x = 625.
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)2} - 100] = Rs. 41/4
? Difference between C.I and S.I = Rs. (41/4 - 10) = Re. 0.25
? 0.25 : 150 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
Let the principle is P
so compound interest = p x ( 1 + (12.5/100))sup>2 - p = 170
? p x (112.5/100) x (112.5/100) - p = 170
? P [ 12656.25 - 10000 ] = 170 x 10000
? p = (170 x 10000) / 2656.25
Simple interest SI = (P x T x R )/100
= [{(170 x 10000) / 2656.25} x 2 x 12.5] / 100
= 160
Let the sum be P.
Then, 1352 = P(1 +4/100)2
? 1352 = P x 26/25 x 26/25
? P = (1352 x 25 x 25) / (26 x 26) = 1250
? Principal = Rs. 1250
Let time be t years
? 882 = 800( 1 +5/1000)t
? 882/800 = (21/20)t
? (21/20)2 = (21/20)t
? t =2
? Time = 2years
? Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
= Rs. [ 2800 x 11/10 x 21/20 ]
= Rs. 3234
? Required C.I. = Rs.(3234 - 2800) = Rs .434
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