Weight of the teacher = Total weight of 40 students and teacher - total weight of 40 students
= 41 x 40.5 - 40 x 40 kg
= 60.5kg
New average = 120% of old average
=120% of 18.5
= (120 x 18.5) / 100
= 22.2
Age of coach = Total weight of 4 players and coach - total weight of 4 players
= 5 x 22.2 - 4 x 18.5
= 37 years
Let the age of youngest child be y.
so from question y + (y + 4) + (y + 8) + (y + 12) = 4 x 12
? 4y + 24= 48
? y = 6 years
Production during these 5 days = Total production in a month - production in first 25 days.
= 30 x 58 - 25 x 60
= 240
? Average for last 5 days = 240 / 5
= 48
Let the number of candidate who passed = y
Then, 39y + 15(120 - y) =120 x 35
? 24y= 4200 -1800
? y= 2400 / 24 = 100
Let average of the remaining student be y.
Then from questions ( 5 x 10 ) + ( 5 x 14) + 20y = 30 x 12
? 50 + 70 + 20y = 360
? 20y = 360 ? 120
? 20y = 240
? y = 12.
Let the average for remaining 8 days be Rs. y a day.
Then, ( 4 x 40 ) + 8y = 504
? 8y = 344
? y = 43
? required average Rs. 43
From question
A + B + C = 3 x 84 = 252 ....(i)
A + B + C + D = 4 x 80 = 320 ...(ii)
From eq. (ii) - (i)
D = ( 320 - 252 ) = 68
From question E = D + 3
? E =( 68 + 3 ) = 71
Now , B + C + D + E = 4 x 79 = 316
? B + C + D = 316 ? 71 = 245
So , A = 320 - 245 = 75 kg .
Total present age of the family = 6 x 22
= 132 years
Total age of the family 7 years ago = 132 - 7 x 6
= 90 years
At that time, the number of members was 5
? Average age at time = 90 / 5 years
= 18 years
Let the height of A , B, C be y cm, y cm and (y - 2) cm respectively
Then, y + y + (y - 2) = 163 x 40 - 162 x 37
? 3y - 2 = 526
? y = 176 cm
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