Average problems
- 1. The average of 44 consecutive odd numbers is 144.What is the largest number?
Options- A. 189
- B. 191
- C. 187
- D. 193 Discuss
Correct Answer: 187
- 2. A batsman makes 100 runs in the 25th match of his career. His average runs per match increases by 1.4. Find his average before the 25th match.
Options- A. 65
- B. 55
- C. 75
- D. 45 Discuss
Correct Answer: 65
- 3. A factory buys 10 machines. 2 MachineA, 3 MachineB and rest MachineC. Prices of the machines are Rs 95000, Rs 60000 and Rs 50000 respectively. What is the average cost of these machines?
Options- A. 62000
- B. 68333
- C. 74666
- D. 60500 Discuss
Correct Answer: 62000
- 4. A line cuts the xaxis at the point (3,0) and the yaxis at the point (0,6). What is the equation of the line?
Options- A. x = 2y + 6
- B. y = 2x - 6
- C. x = 2y - 6
- D. y = 2x + 6 Discuss
Correct Answer: y = 2x + 6
- 5. The average weight of P, Q and R is 71 kg. If the average weight of P and Q be 66 kg and that of Q and R be 76.5 kg, then the weight (in kg) of Q is.
Options- A. 60
- B. 72
- C. 81
- D. 75 Discuss
Correct Answer: 72
- 6. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
Options- A. 40
- B. 39
- C. 50
- D. 55 Discuss
Correct Answer: 39
Explanation:
Let the average after 17th innings = x
Then average after 16th innings = (x - 3)
Therefore 16 × (x - 3) + 87 = 17x
Therefore x = 39
- 7. The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?
Options- A. 76
- B. 79
- C. 85
- D. 87 Discuss
Correct Answer: 76
Explanation:
Average = total runs / no.of innings = 32
So, total = Average x no.of innings = 32 x 10 = 320.
Now increase in avg = 4runs. So, new avg = 32+4 = 36runs
Total runs = new avg x new no. of innings = 36 x 11 = 396
Runs made in the 11th inning = 396 - 320 = 76
- 8. A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
Options- A. 4991
- B. 5467
- C. 5987
- D. 6453 Discuss
Correct Answer: 4991
Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (39000 - 34009)
= Rs. 4991.
- 9. The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?
Options- A. 0
- B. -1
- C. 1
- D. none of these Discuss
Correct Answer: 0
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers = (0 * 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).
- 10. The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ?
Options- A. 70 kg
- B. 75 kg
- C. 80 kg
- D. 85 kg Discuss
Correct Answer: 85 kg
Explanation:
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.