Area =  1 2 * d i a g o n a l 1 * 1 2 d i a g o n a l 2 =  1 2 * 24 * 10 sq.cm  

1 2 * d a i g o n a l 1 = 1 2 * 24 = 12 c m 

1 2 * d i a g o n a l 2 = 1 2 * 10 = 5 c m 

side of a rhombus = (12)² + (5)² = 169      => AB = 13cm

In this type of question, we will first calculate the distance covered in given time.

Distance covered will be : Number of revolutions x Circumference 

So we will be having distance and time, from which we can calculate the speed. 

Radius of wheel = 70 / 2 = 35 cm

Distance covered in 40 revolutions will be  40 * c i r c u m f e r e n e = 40 * 2 ?r = 40 * 2 * 22 7 * 35 = 8800 cm = 88 m

Distance covered in 1 sec  =  88 10 = 8 . 8 m / s = 8 . 8 * 18 5 k m / h r = 31 . 68 k m / h r

a =  1 2 × 15 × 12 = 90 sq.cm  

b = 2a =  1 2 × 20 × h  

h= 18cm

let inner radius be r meters. 

$$\begin{gathered} 2 ?r = 440 ? r = 440 × 7 44 = 70 m \\ radius of outer circle = 70 + 14 m \end{gathered}$$  

Therefore, Radius of outer circle = 70 + 14 = 84m

Because each vertice of the square is the center of a circle
(1/4) part of the total area of each circle inside of the square.
(3/4) part of the total area of each circle outside of the square.
Thus total area outside the square is 4 3 4 × 22 7 × 3 . 5 × 3 . 5 = 115.3955 sq cm.

Area = (l + b ? d) d

= (80 + 60 ? 10)10

=> 1300 sq.mts

=> 1300 x 3 = Rs.3900

Let the breadth of rectangle be x m.

Then, the length of rectangle = (x+ 6) m

Perimeter of rectangle = 2 (x+x+ 6) m

Therefore, 2 (x+x+ 6) = 84 m

4x+ 12 = 84

4x= 84 ?12
4x = 72/4 = 18
Therefore, length of rectangle = 18 + 6 = 24 m = height of triangle

Diagonal of rectangle = ?(324+576) = 30 m = base of triangle

Therefore, are of triangle =1/2× base × height =1/2× 24 × 30 = 360 sq. m

Let the length of the rectangle be 3x and breadth be 1x
Given, perimeter = 96 m
2(l + b) = 96 (or) l + b = 48 (or) 3x + 1x = 48 (or) x = 12 m
Now, Length of the rectangle = 12 x 3 = 36 m