Area problems
- 1. A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Options- A. 1
- B. 2
- C. 3
- D. 4 Also asked in: Bank Exams, Bank PO
Correct Answer: 3
Explanation:
Area of the park = (60 x 40) = 2400
Area of the lawn = 2109
Area of the crossroads = (2400 - 2109) = 291
Let the width of the road be x metres. Then,
(x - 97)(x - 3) = 0
x = 3.
- 2. The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.
Options- A. B=900;H=300
- B. B=300;H=900
- C. B=600;H=700
- D. B=500;H=900 Also asked in: Bank Exams, Bank PO
Correct Answer: B=900;H=300
Explanation:
Area of the field = Total cost/rate = (333.18/25.6) = 13.5 hectares
Let altitude = x metres and base = 3x metres.
Then,
Base = 900 m and Altitude = 300 m.
- 3. A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is
Options- A. Rs. 258
- B. Rs. 358
- C. Rs. 458
- D. Rs. 558 Also asked in: Bank Exams, Bank PO
Correct Answer: Rs. 558
Explanation:
Area to be plastered =
=
Cost of plastering =
- 4. The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?
Options- A. 3 cm
- B. 4 cm
- C. 6 cm
- D. 8 cm Also asked in: Bank Exams, Bank PO
Correct Answer: 6 cm
Explanation:
Let height =x Then, base =2x
2x * x = 72
=>x=6
- 5. The ratios of areas of two squares, one having its diagonal double than the other is
Options- A. 2:1
- B. 2:3
- C. 3:1
- D. 4:1 Also asked in: Bank Exams, Bank PO
Correct Answer: 4:1
Explanation:
ratio =
- 6. A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?
Options- A. 156
- B. 166
- C. 176
- D. 186 Also asked in: Bank Exams, Bank PO
Correct Answer: 176
Explanation:
Area of the room=(544 * 374)
size of largest square tile= H.C.F of 544 & 374 = 34 cm
Area of 1 tile = (34 x 34)
Number of tiles required== [(544 x 374) / (34 x 34)] = 176
- 7. Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.
Options- A. 30
- B. 40
- C. 50
- D. 60 Also asked in: Bank Exams, Bank PO
Correct Answer: 30
Explanation:
Height of the triangle = = 5 cm.
Its area = = = .
- 8. The length of a rectangle is twice its breadth if its length is decreased by 5cm and breadth is increased by 5cm, the area of the rectangle is increased by 75 sq cm. Find the length of the rectangle.
Options- A. 30
- B. 40
- C. 50
- D. 60 Also asked in: Bank Exams, Bank PO
Correct Answer: 40
Explanation:
let length = 2x and breadth = x then
(2x-5) (x+5) = (2x * x)+75
5x-25 = 75 => x=20
length of the rectangle = 40 cm
- 9. The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?
Options- A. 150
- B. 250
- C. 350
- D. 550 Also asked in: Bank Exams, Bank PO
Correct Answer: 250
Explanation:
Circumference = No.of revolutions * Distance covered
Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.
- 10. A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.
Options- A. 136
- B. 146
- C. 166
- D. 176 Also asked in: Bank Exams, Bank PO
Correct Answer: 176
Explanation:
area of the room = 544 x 374 sq.cm
size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm
area of 1 tile = 34x34 sq cm
no. of tiles required = (544 x 374) / (34 x 34) = 176
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