Area problems
- 1. The area of a circle is 346.5 cm2. Find its circumference (in cm).
Options- A. 132
- B. 38
- C. 66
- D. 76 Also asked in: Bank Exams
Correct Answer: 66
- 2. Find the total surface area (in cm2) of a cube of side 7.5 cm.
Options- A. 364.5
- B. 446
- C. 337.5
- D. 684 Also asked in: Bank Exams
Correct Answer: 337.5
- 3. Area of circle is equal to the area of a rectangle having perimeter of 50 cms. and length more than the breadth by 3 cms. What is the diameter of the circle?
Options- A. 7 cms
- B. 21 cms
- C. 28 cms
- D. 14 cms Discuss
Correct Answer: 14 cms
Explanation:
Let the breadth of rectangle be x cm => Length of rectangle = (x+3) cm Now, perimeter =2(x+x+3) = 50 => 2x + 3 = 25 => x = 11 Thus, breadth = 11 cm and length = 14 cm Area of circle = Area of rectangle =>pi * r* r = 14 * 11 =>r*r = 14 * 11 * 7/22 =>r = 7 cm Diameter = 2 * 7 = 14 cm
- 4. The length of the diagonal of a square is 14 cm. What is area of this square?
Options- A. 49 sq cm
- B. 196 sq cm
- C. 98 sq cm
- D. 77 sq cm Also asked in: Bank Exams
Correct Answer: 98 sq cm
- 5. The circumferences of two circles are touching externally. The distance between their centres is 12 cm. The radius of one circle is 7 cm. Find the diameter(in cm) of the other circle.
Options- A. 12
- B. 10
- C. 8
- D. 5 Also asked in: Bank Exams
Correct Answer: 10
- 6. The area and the length of one of the diagonals of a rhombus is 84 cm² and 7 cm respectively. Find the length of its other diagonal (in cm).
Options- A. 12
- B. 24
- C. 48
- D. 36 Also asked in: Bank Exams
Correct Answer: 24
- 7. Find the perimeter (in cm) of a semicircle of radius 28 cm.
Options- A. 288
- B. 144
- C. 121
- D. 242 Also asked in: Bank Exams
Correct Answer: 144
- 8. ABCD is a quadrilateral inscribed in a circle (radius = ). The bisectors of the angles DAB and BCD intersect the circle at X and Y, respectively. What is the length of the straight line XY?
Options- A. ? (rxr)
- B. 2r
- C. (r + 2)
- D. ? (rxr)/2 Also asked in: Bank Exams
Correct Answer: 2r
- 9. A tent is to be built in the form of a cylinder of radius 10 m surmounted by a cone of the same radius. If the height of the cylindrical part is 5 m and slant height of the conical part is 15 m, how much canvas will be required to build the tent? Allow 20% extra canvas for folding and stitching. (Take ? = 22/7)
Options- A. 4714.43 sq m
- B. 3772.14 sq m
- C. 6783.86 sq m
- D. 2451.42 sq m Discuss
Correct Answer: 2451.42 sq m
- 10. There is a square field of area ?X? square meters. A cylindrical ditch of radius 7 meters and depth 2 meters is dug, and the earth is taken out and spread over the remaining part of the square field, the height of square field which goes up by 0.77 meters. What is the value of ?X? ?
Options- A. 548 sq. m
- B. 524 sq. m
- C. 518 sq. m
- D. 554 sq. m Also asked in: AIEEE, Bank Exams
Correct Answer: 554 sq. m
Explanation:
Volume of the cylindrical ditch = ?rxrh = 22/7 ×7×7×2 = 308 sq.m
Area of remaining field = (X ??rxr) sq.m
= (X ? 154)
ATQ ?
(X ? 154) ×0.77 = 308
(X ? 154) = 400
X= 554 sq.m
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