let each side of the square be a , then area = a 2 

As given that The side is increased by 25%, then 

New side = 125a/100 = 5a/4 

New area =  5 a 4 2  

Increased area=  25 a 2 16 - a 2 

Increase %= 9 a 2 / 16 a 2 * 100  % = 56.25%

let length = x and breadth = y then  

2(x+y) = 46         =>   x+y = 23  

x²+y² = 17² = 289  

now (x+y)² = 23² 

=> x²+y²+2xy= 529 

=> 289+ 2xy = 529

=> xy = 120  

area = xy = 120 sq.cm

Let original radius = R. 

New radius =  50 100 R=  50 100 R 

Original area = R 2  and new area =  ?R 2

3 ?R 2 4 * 1 ?R 2 * 100 

Decrease in area =  ? R 2 2 = ?R 2 4 = 75%

l 2 + b 2 = 41 (or)    l 2 + b 2 = 41  

Also,  l b = 20

l + b 2 = l 2 + b 2 + 2 l b  = 41 + 40 = 81

(l + b) = 9. 

Perimeter = 2(l + b) = 18 cm.

let ABCD be the given parallelogram 

area of parallelogram ABCD = 2 x (area of triangle ABC) 

now a = 30m, b = 14m and c = 40m

 s=1/2 x (30+14+40) = 42 

Area of triangle ABC =  s s - a s - b s - c  

= 42 12 28 2= 168sq m 

area of parallelogram ABCD = 2 x 168 = 336 sq m