Amount of pure milk= a(1 ?b/a)n(n = 3, a = pure milk and b = amount replaced)= 960 (1 ?48/960)^3= 960(1-1/20)^3= 960 * 19/20 * 19/20*19/20= 823.08 lt.
Let the quantity of the wine in the cask originally be x litres
Then, quantity of wine left in cask after 4 operations =
litres
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