Logical puzzle At a restaurant, how could you choose one out of three desserts with equal probability with the help of a coin? What if the coin is biased and the bias is unknown?

Correct Answer: Our solution: Toss the coin twice Let TH, HT and TT correspond to the three choices And if you get HH, just repeat (so it takes 8/3 tosses on average) BIASED COIN If the coin was biased, TH and HT would occur with equal probability So you could assign THHT, HTTH and THTH to the three choices, with other 4-toss outcomes rejected Or you could assign HTT, THT and TTH to the three choices, with other 3-toss outcomes rejected