Difficulty: Medium
Correct Answer: d(CES)/dt = 0 (enzyme–substrate complex concentration is approximately constant)
Explanation:
Introduction / Context:The Michaelis–Menten model commonly employs the pseudo (quasi) steady-state assumption (QSSA) to derive a tractable rate law. This approximation asserts that the concentration of the enzyme–substrate complex ES rapidly reaches a near-constant value relative to slower changes in substrate and product, enabling algebraic elimination of ES from the differential equations.
Given Data / Assumptions:
Concept / Approach:Under QSSA, the time derivative of ES is approximately zero: d(ES)/dt ≈ 0. This means ES forms and breaks down at similar rates, allowing steady concentration despite ongoing conversion of S to P. The condition is valid when substrate is much greater than enzyme and after the short pre-steady-state phase.
Step-by-Step Solution:
1) Write mass balances for E, S, ES, and P.2) Assume d(ES)/dt ≈ 0 following the rapid transient.3) Use conservation CE = E + ES to eliminate E.4) Solve algebraically to obtain v = Vmax * S / (KM + S).Verification / Alternative check:Pre-steady-state kinetic experiments show an initial burst phase after which ES is nearly constant, supporting QSSA under typical conditions (S » E).
Why Other Options Are Wrong:
Common Pitfalls:Confusing total enzyme conservation with the ES steady-state requirement; ignoring the initial transient when QSSA may not hold.
Final Answer:d(CES)/dt = 0 (enzyme–substrate complex concentration is approximately constant)
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