Difficulty: Easy
Correct Answer: hyperbolic process
Explanation:
Introduction / Context:Many thermodynamic processes are classified by simple functional relations among p, v, and T. Recognizing the label associated with p * v = constant helps with quick diagramming and integration of work terms.
Given Data / Assumptions:
Concept / Approach:The general polytropic relation is p * v^n = constant. When n = 1, the p–v curve is a rectangular hyperbola, and the process is called a hyperbolic process. For an ideal gas, an isothermal process also satisfies p * v = m * R * T = constant if temperature is constant; thus, for ideal gases, a hyperbolic process with n = 1 coincides with isothermal. However, the broader, name-by-equation classification is “hyperbolic.”
Step-by-Step Solution:
Write the observed law: p * v = C.Compare with polytropic form p * v^n = C → n = 1.Therefore, classify as a hyperbolic (n = 1) process.Verification / Alternative check:On a p–v plot, p = C/v gives a rectangular hyperbola; the area under the curve ∫p dv = C * ln(v2/v1) is the characteristic work expression for n = 1.
Why Other Options Are Wrong:
Common Pitfalls:Assuming p * v = constant automatically implies no heat transfer; that is only guaranteed for ideal-gas isothermal processes, not for real gases or non-ideal conditions.
Final Answer:hyperbolic process
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