IBPS PO Mains Paper 2024
Interactive Study & Solution Mode
Question 4 of 155
Read the following passage and answer the given questions. A word and number sorting machine, when given an input of words and numbers, rearranges them in a particular manner step by step, as indicated below, until all the words and numbers are arranged. Given below is an illustration of this arrangement. Input: 37 50 FGN KZU 74 YNS 51 100 ORS 17 HPBM Step 1: 100 37 50 FGN KZU 74 YNS ORS 17 HPBM 51 Step 2: 74 100 50 FGN KZU YNS ORS 17 HPBM 51 37 Step 3: 50 74 100 FGN KZU YNS ORS HPBM 51 37 17 Step 4: 50 74 100 EFGNM KZU YNS ORS HPBM 51 37 17 Step 5: 50 74 100 EFGNM GHPBML KZU YNS ORS 51 37 17 Step 6: 50 74 100 EFGNM GHPBML JKZUT YNS ORS 51 37 17 Step 7: 50 74 100 EFGNM GHPBML JKZUT NORSR YNS 51 37 17 Step 8: 50 74 100 EFGNM GHPBML JKZUT NORSR XYNSR 51 37 17 And, step 8 is the last step of the above input, as per the rules followed in the steps given above; find out in each of the following questions the appropriate step for the given input. Input: ETU 75 GTQ 14 RTV 22 NTS 32 MTW 67 FSN 19 CER What is the position of 'EFSNM' in the step 7?
Aptitude
Sequential Output Tracing
Difficulty: Hard
Choose an option
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ASeventh from the left
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BSeventh from the right
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CFifth from the right
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DSixth from the left
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ENone of these
Answer
Correct Answer: Sixth from the left
Explanation
### Concept & Pattern Logic
In sequential output tracing, we must first decode the hidden rules applied to numbers and words by analyzing the illustration.
**1. Number Logic:** In the first 3 steps, numbers are arranged. The highest even number goes to the extreme left, and the highest odd number goes to the extreme right.
**2. Word Logic:** Once numbers are sorted, words are arranged alphabetically one by one. During arrangement, each word transforms by adding its first letter's predecessor to the front and its last letter's predecessor to the end.
### Step-by-Step Solution
Let us trace the given input fully based on the decoded logic.
**Input:** ETU 75 GTQ 14 RTV 22 NTS 32 MTW 67 FSN 19 CER
**Sorting Numbers:**
* **Step 1:** 32 ETU GTQ 14 RTV 22 NTS MTW 67 FSN 19 CER 75
* **Step 2:** 22 32 ETU GTQ 14 RTV NTS MTW FSN 19 CER 75 67
* **Step 3:** 14 22 32 ETU GTQ RTV NTS MTW FSN CER 75 67 19
**Sorting Words:**
* **Step 4 (CER $\rightarrow$ BCERQ):** 14 22 32 BCERQ ETU GTQ RTV NTS MTW FSN 75 67 19
* **Step 5 (ETU $\rightarrow$ DETUT):** 14 22 32 BCERQ DETUT GTQ RTV NTS MTW FSN 75 67 19
* **Step 6 (FSN $\rightarrow$ EFSNM):** 14 22 32 BCERQ DETUT EFSNM GTQ RTV NTS MTW 75 67 19
* **Step 7 (GTQ $\rightarrow$ FGTQP):** 14 22 32 BCERQ DETUT EFSNM FGTQP RTV NTS MTW 75 67 19
We look at Step 7: 14 22 32 BCERQ DETUT EFSNM FGTQP RTV NTS MTW 75 67 19.
Counting from the left:
1. 14
2. 22
3. 32
4. BCERQ
5. DETUT
6. EFSNM
Therefore, 'EFSNM' is the 6th element from the left. Checking from the right (13 elements total): $13 - 6 + 1 = 8$th from the right, which is not an option.
### Exam Strategy & Shortcut
To find the position of a sorted word quickly in a later step, you can simply count the fixed elements. In step 7, we know 3 numbers are fixed on the left, and 4 words have been sorted so far (CER, ETU, FSN, GTQ). FSN is the 3rd sorted word. So its position is $3 \text{ (numbers)} + 3 \text{ (its rank among words)} = 6$th position from the left.
### Common Pitfall
A common mistake is forgetting to count the initial numbers that were grouped on the left, resulting in an off-by-three error.
### Final Answer
Therefore, the correct answer is **Sixth from the left**.