Difficulty: Medium
Correct Answer: Competitive inhibition is smaller than uncompetitive inhibition
Explanation:
Introduction / Context:
Many real inhibitors display mixed behavior, exerting both competitive (affecting K m) and uncompetitive (affecting V max and K m together by binding ES) components. When one component dominates, we label the overall pattern accordingly. This question asks how to label a case where the uncompetitive component predominates.
Given Data / Assumptions:
Concept / Approach:
If the inhibitor binds ES much more strongly than E (K i,ES << K i,E), the uncompetitive effect dominates. In practice, we compare the magnitudes of the competitive and uncompetitive contributions; if the uncompetitive term is larger, we call the pattern predominantly uncompetitive.
Step-by-Step Solution:
Verification / Alternative check:
On Lineweaver–Burk plots, pronounced uncompetitive behavior yields roughly parallel lines (decreased V max and K m by the same factor), outweighing any x-intercept shifts caused by a competitive component.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing “uncompetitive” with “noncompetitive (pure)”—pure noncompetitive is the special case K i,E = K i,ES; predominantly uncompetitive means K i,ES is effectively lower so ES binding dominates.
Final Answer:
Competitive inhibition is smaller than uncompetitive inhibition
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