Difficulty: Medium
Correct Answer: Rapid equilibrium conditions with equal affinity for E and ES
Explanation:
Introduction / Context:
Classical noncompetitive (the pure case) is a limiting scenario of mixed inhibition where the inhibitor binds free enzyme (E) and the enzyme–substrate complex (ES) with equal affinity. Experimentally, the cleanest expression of this behavior appears under rapid equilibrium assumptions.
Given Data / Assumptions:
Concept / Approach:
With rapid equilibrium and equal affinities, the apparent K m stays constant while V max decreases by 1/(1 + I/Ki). This yields Lineweaver–Burk lines intersecting on the x-axis (constant −1/Km) and increasing slopes with inhibitor.
Step-by-Step Solution:
Verification / Alternative check:
Global fitting of v vs [S] data to the pure noncompetitive model reproduces unchanged x-intercepts with decreased y-intercepts, matching the rapid-equilibrium prediction.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing pure noncompetitive with mixed inhibition where Ki,E ≠ Ki,ES, which alters Km as well as Vmax.
Final Answer:
Rapid equilibrium conditions with equal affinity for E and ES
Discussion & Comments