Linear population change: City A has population 136000 decreasing by 2400 per year, and City B has population 84000 increasing by 1600 per year. After how many years will their populations be equal?

Difficulty: Easy

Correct Answer: 13

Explanation:


Introduction / Context:
This problem models two populations changing linearly but in opposite directions. We set both expressions equal and solve for time. It is a straightforward linear equation in t (years).


Given Data / Assumptions:

  • City A at t years: A(t) = 136000 - 2400*t
  • City B at t years: B(t) = 84000 + 1600*t
  • Equality A(t) = B(t)


Concept / Approach:
Equate A(t) and B(t) to find the year where the populations match. Since both changes are linear with constant rates, a single solution exists if rates differ.


Step-by-Step Solution:

136000 - 2400t = 84000 + 1600t136000 - 84000 = 1600t + 2400t52000 = 4000tt = 52000 / 4000 = 13


Verification / Alternative check:

A(13) = 136000 - 2400*13 = 136000 - 31200 = 104800B(13) = 84000 + 1600*13 = 84000 + 20800 = 104800 (matches)


Why Other Options Are Wrong:

  • 15, 18, 19: Substitution yields mismatched populations, so they are incorrect.


Common Pitfalls:

  • Sign errors when moving terms (mixing +1600t and -2400t).
  • Arithmetic errors dividing 52000 by 4000.


Final Answer:

13

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