The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Aptitude
Percentage
Difficulty: Medium
Choose an option
Answer
Correct Answer: 4.14% per year
Explanation
Given
- Initial population P0 = 1,75,000
- Population after 10 years P10 = 2,62,500
Concept
The average annual percent increase is the CAGR: ( π 10 / π 0 ) 1 / 10 β 1 (P 10 β /P 0 β ) 1/10 β1.
Step 1: Compute the growth factorGrowth factor = 2 , 62 , 500 1 , 75 , 000 = 1.5 1,75,000 2,62,500 β =1.5
Step 2: Compute CAGRCAGR = 1.5 1 / 10 β 1 1.5 1/10 β1Using ln/exponent: ln(1.5) β 0.405465; divide by 10 β 0.0405465; exp β 1.04141CAGR β 1.04141 β 1 = 0.04141 = 4.14% per year
Final AnswerAverage percent increase β 4.14% per year.