Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:The barrier potential is central to understanding diode I-V behavior, rectification, and switching. It is the internal voltage that forms spontaneously when p-type and n-type regions are joined, creating a depletion region and establishing equilibrium.
Given Data / Assumptions:
Concept / Approach:At the moment of contact, electrons diffuse from n to p, and holes from p to n, leaving behind charged ions. This uncovered charge region (depletion) creates an electric field and a potential difference called the built-in or barrier potential. This potential opposes further diffusion. The magnitude depends on doping concentrations and temperature and is typically around 0.2–0.9 V for common materials (lower for Ge, higher for Si).
Step-by-Step Solution:
1) Form a pn junction by bringing p and n materials into contact.2) Carriers diffuse, leaving uncovered ionized dopants near the junction.3) The resulting field establishes a potential step (barrier potential).4) Equilibrium occurs when drift and diffusion currents cancel.Verification / Alternative check:Deriving the built-in voltage from semiconductor physics yields V_bi proportional to the logarithm of the product of dopant concentrations divided by intrinsic carrier density squared, consistent with the qualitative description.
Why Other Options Are Wrong:Incorrect: ignores the well-established depletion region mechanism.
Only at 0 K or only under forward bias: V_bi exists at normal temperatures without external bias; forward bias reduces the effective barrier seen by carriers.
Common Pitfalls:Confusing the internal barrier with applied forward voltage; assuming ions move (they are fixed in the lattice); overlooking temperature dependence.
Final Answer:Correct
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