Intel 8088 architecture basics Pick the correct combination for the Intel 8088 CPU: internal word size and external data bus width.

Introduction / Context:
The Intel 8088 powered the original IBM PC. Technicians studying PC history or supporting embedded systems based on 8088 derivatives should know its internal and external bus characteristics.

Given Data / Assumptions:

• 8088 is closely related to the 8086, but with a narrower external data bus.
• Word size refers to the CPU's internal register width and instruction set data size.

Concept / Approach:

The 8088 has a 16-bit internal architecture (registers and ALU) but an 8-bit external data bus, enabling cheaper system designs using 8-bit components while retaining 16-bit internal processing—one reason IBM chose it for the first PC.

Step-by-Step Solution:

Verification / Alternative check:

Intel datasheets and PC technical references confirm 8088's 8-bit external data bus and 16-bit internal registers (AX, BX, etc.).

Why Other Options Are Wrong:

Options B and E assign an 8-bit word size, which is incorrect. Option C describes the 8086, not the 8088. Option D assigns a 4-bit word size, which is unrelated to 8088.

Common Pitfalls:

Confusing 8088 with 8086; equating external bus width with CPU word size; overlooking the cost/design motivations for using the 8088 in early PCs.

Final Answer:

16 bit word size, 8 bit data path.