Phototransistor operation — control mechanism: A phototransistor’s conduction, and thus its output state in interfacing circuits, is governed by the presence or absence (and intensity) of incident light acting as an effective base drive. Evaluate this statement’s accuracy.
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ACorrect
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BIncorrect
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CCorrect only when an external base lead is used
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DValid exclusively for photodiodes, not phototransistors
Answer
Correct Answer: Correct
Explanation
Introduction / Context:Opto-sensors such as phototransistors are common in digital input conditioning, opto-isolators, and light detection. Understanding how light influences their conduction clarifies why pull-ups, biasing, and thresholding are arranged as they are in interface circuits.
Given Data / Assumptions:
- A phototransistor responds to photons that generate carriers, effectively providing base current.
- Many phototransistors omit a discrete base lead; light acts as the stimulus.
- External biasing and load resistors translate collector current into a voltage.
Concept / Approach:Incident light increases the effective base drive, raising collector current and changing the voltage across the load. In common-emitter configurations with a pull-up, more light typically pulls the output node LOW (more current through the transistor), while in other topologies the logic polarity can be inverted. The essence remains: light presence/absence controls conduction.
Step-by-Step Solution:Model the device as a BJT with optically induced base current.More light → more carriers → higher collector current.Translate current to voltage with the load to obtain a logic-level signal.Set thresholds so ambient variations do not cause false triggers.
Verification / Alternative check:Datasheets specify “collector current vs irradiance” curves confirming monotonic response to light intensity.
Why Other Options Are Wrong:Requiring an external base lead is unnecessary; many packages are base-less. Photodiodes differ in operation (reverse-biased junction current) though both are light-sensitive; the statement correctly concerns phototransistors.
Common Pitfalls:Ignoring ambient light; failing to add hysteresis; misinterpreting logic polarity based on wiring configuration.
Final Answer:Correct