Parallel circuits and fault conditions: if one branch opens in a parallel network driven by an ideal voltage source, will the current in the remaining parallel paths change or remain the same (ignoring source internal resistance)?

Introduction / Context:
Parallel circuits appear throughout electronics and power distribution. Understanding how branch currents respond when one branch opens is essential for diagnostics and reliability analysis. The statement under test claims that when one branch opens, the current in the remaining branches changes. We evaluate this under the standard ideal-source model used in circuit theory.

Given Data / Assumptions:

• Ideal constant-voltage source feeds the parallel network.
• Branch resistances are linear and time-invariant.
• No significant source internal resistance unless explicitly mentioned.

Concept / Approach:
In a parallel network with an ideal voltage source, each branch current is I_k = V / R_k. If a different branch opens, the source voltage V applied to the remaining branches does not change, and their resistances do not change either. Therefore I_k for all remaining branches remains the same. Only the total supply current and equivalent resistance change.

Step-by-Step Solution:

Verification / Alternative check:
If non-ideal source resistance exists, V may sag slightly when load changes. The ideal model used in introductory analysis assumes V is fixed, justifying the conclusion.

Why Other Options Are Wrong:
Correct: contradicts ideal-source analysis.
Depends on source internal resistance: outside the stated ideal assumption.
Cannot be determined: sufficient information is present under standard assumptions.

Common Pitfalls:
Confusing total current with branch currents; assuming voltage sources act like current sources; overlooking internal resistance only when it is actually specified.

Final Answer:
Incorrect