Current division insight — in a parallel circuit, the branch having the largest resistance will have which relative current compared with other branches?

Introduction / Context:
Current division governs how source current splits among parallel branches. Since all branches share the same voltage, the branch current depends inversely on its resistance (Ohm’s law).

Given Data / Assumptions:

• Ideal DC conditions, lumped components.
• Branches are purely resistive for this question.
• Each branch sees the same node-to-node voltage.

Concept / Approach:
Ohm’s law: I = V/R. With equal V across branches, higher R implies lower I. Thus, the largest resistance carries the smallest current. Voltage across each branch is equal and equals the source voltage.

Step-by-Step Solution:

Verification / Alternative check:
Compute a quick example (V = 12 V; R = 6 kΩ vs 12 kΩ). Currents are 2 mA and 1 mA respectively, confirming the inverse relation.

Why Other Options Are Wrong:

Common Pitfalls:
Confusing series/parallel attributes; thinking voltage divides in parallel (it does not).

Final Answer:
Least current