Capacitance rule (repaired stem) — in a parallel combination that includes capacitor C4 along with other capacitors, the total capacitance is larger than the value of C4 alone. Is this statement correct?

Introduction / Context:Knowing how total capacitance compares to individual branch values helps validate designs quickly. In parallel, capacitances add directly, so the total must exceed each individual branch value.

Given Data / Assumptions:

• Capacitors are connected in parallel, including C4 among them.
• Capacitors behave linearly in the operating region.

Concept / Approach:Parallel rule: CT = C1 + C2 + … + Cn. Since each Ci ≥ 0, CT ≥ any Ci, with strict inequality if at least one additional capacitor is present besides C4.

Step-by-Step Solution:

Verification / Alternative check:Example: C4 = 10 µF in parallel with 2.2 µF → CT = 12.2 µF > 10 µF.

Why Other Options Are Wrong:

Common Pitfalls:Confusing series vs parallel behavior; in series, the total is less than the smallest element, which is the opposite trend.

Final Answer:Correct