Inverting input drive — output polarity: When an input signal is applied to the inverting input of an op-amp and the noninverting input is grounded, what is the polarity of the output relative to the input (within the linear range)?
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AOpposite polarity (inverted) with magnitude set by the closed-loop gain
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BSame polarity (noninverted) regardless of gain
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CNo output because the noninverting input is grounded
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DRandom polarity depending only on temperature
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EAlways clipped at the positive rail
Answer
Correct Answer: Opposite polarity (inverted) with magnitude set by the closed-loop gain
Explanation
Introduction / Context:The inverting op-amp configuration is one of the first linear circuits taught. Its hallmark is a 180-degree phase inversion between input and output. Recognizing this helps when chaining stages, summing signals, or designing active filters with correct phase response.
Given Data / Assumptions:
- Ideal op-amp with negative feedback.
- Noninverting input tied to ground reference.
- Signal applied through an input resistor to the inverting input.
Concept / Approach:With the noninverting input at 0 V, feedback keeps the inverting input near 0 V (virtual ground). The closed-loop gain is −Rf/Rin, a negative value indicating inversion. Thus, a positive input produces a negative output, and vice versa, until limited by the supply rails.
Step-by-Step Solution:
Write v_out = −(Rf/Rin) * v_in.Note the negative sign → 180-degree inversion.Magnitude determined by |Rf/Rin|; ensure |v_out| stays within rails.Therefore, output is opposite in polarity to the input.Verification / Alternative check:Oscilloscope shows input and output sinusoidal waveforms inverted by half a cycle with amplitude ratio equal to |Rf/Rin|. Step response also inverts polarity instantly, within slew limits.
Why Other Options Are Wrong:
Same polarity: describes noninverting configuration.No output: incorrect—grounding the noninverting input is normal for inverting stages.Random/clipped: not intrinsic unless overdriven or poorly biased.Common Pitfalls:Ignoring output swing limits; forgetting to include input bias cancellation when using large resistances; miswiring Rin and Rf leading to positive feedback.
Final Answer:Opposite polarity (inverted) with magnitude set by the closed-loop gain