Difficulty: Easy
Correct Answer: 1
Explanation:
Introduction / Context:When a root of a polynomial is known, substituting it into the equation yields a direct relation among parameters. Here, plugging x = 5 into the quadratic allows us to solve for k in one step.
Given Data / Assumptions:
Concept / Approach:If r is a root, then r satisfies the equation identically. Substitute r = 5 and solve the resulting linear equation for k. No need for the quadratic formula here.
Step-by-Step Solution:
5^2 − 6k*5 + 5 = 025 − 30k + 5 = 0 ⇒ 30 − 30k = 0k = 1Verification / Alternative check:With k = 1, equation becomes x^2 − 6x + 5 = 0, which factors as (x − 1)(x − 5) = 0, confirming 5 is indeed a root.
Why Other Options Are Wrong:
Common Pitfalls:Forgetting to multiply 6k by x or mishandling algebraic signs when combining constants.
Final Answer:1
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