Solve the quadratic completely: Find the roots of 2x^2 − 9x − 18 = 0.

Difficulty: Easy

Correct Answer: -3/2 and 6

Explanation:


Introduction / Context:
We solve a quadratic equation using the quadratic formula or by factoring if possible. The discriminant indicates whether the roots are real and helps simplify radicals when they are perfect squares.


Given Data / Assumptions:

  • Equation: 2x^2 − 9x − 18 = 0
  • a = 2, b = −9, c = −18


Concept / Approach:
Use the quadratic formula x = [−b ± √(b^2 − 4ac)]/(2a). Since the discriminant is a perfect square, the roots will be rational and can be presented in fractional form.


Step-by-Step Solution:

D = b^2 − 4ac = (−9)^2 − 4*2*(−18) = 81 + 144 = 225√D = √225 = 15x = [9 ± 15]/(2*2) = (9 ± 15)/4Roots: x = 24/4 = 6 and x = −6/4 = −3/2


Verification / Alternative check:
Substitute x = 6: 2*36 − 54 − 18 = 0. Substitute x = −3/2: 2*(9/4) + (27/2) − 18 = 0. Both satisfy the equation.


Why Other Options Are Wrong:

  • 3/2 and 6; 3/2 and −6; −3/2 and −6: Each pair has at least one sign incorrect.
  • −6 and 6: −6 is not a root; −3/2 is.


Common Pitfalls:
Dropping the negative sign on b or mishandling the division by 2a when simplifying.


Final Answer:
-3/2 and 6

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