In this odd one out question based on letters, select the pair that does not follow the same pattern as the others: AE, IO, UA and GH.

Introduction / Context:
Reasoning questions involving small groups of letters often rely on basic properties such as vowels and consonants. In this problem, four two letter combinations are given, and you are asked to find the one that does not belong to the same family as the others. This is a classic example of an odd one out question that tests your understanding of the English alphabet and classification of letters.

Given Data / Assumptions:

• The options are: AE, IO, UA and GH.
• We treat A, E, I, O, U as vowels and the remaining letters as consonants.
• The task is to pick the pair whose composition of vowels and consonants differs from the rest.

Concept / Approach:
A straightforward technique is to check whether each pair consists of vowels, consonants, or a mix of both. Patterns like both vowels, both consonants or vowel consonant combinations are frequently used to build such questions. Once we identify the majority type among the options, the pair that does not share that structure is declared the odd one out.

Step-by-Step Solution:
Step 1: Examine AE. A is a vowel and E is also a vowel. So AE is a pair of vowels. Step 2: Examine IO. I is a vowel and O is a vowel, so IO is also a vowel pair. Step 3: Examine UA. U is a vowel and A is a vowel, so UA again forms a pair made only of vowels. Step 4: Examine GH. G is a consonant and H is a consonant, so GH is a consonant pair, not a vowel pair. Step 5: Since AE, IO and UA each contain two vowels, while GH contains two consonants, GH is the odd one out.

Verification / Alternative check:
We can confirm by simply writing V for vowel and C for consonant. The pairs become: AE = VV, IO = VV, UA = VV and GH = CC. Three pairs are VV and one pair is CC. The single CC pair is clearly different. There is no need for any deeper arithmetic or positional logic in this particular question, because the vowel consonant pattern already gives a clean and unique classification.

Why Other Options Are Wrong:
AE is wrong as the odd one out because, like IO and UA, it is formed by two vowels. IO is wrong as the odd one out because it also has the same property of being a vowel pair. UA is wrong as the odd one out because it is yet another pair made up entirely of vowels.

Common Pitfalls:
Students sometimes overcomplicate such questions by checking letter positions or trying to find numerical patterns in the alphabet indexes. While that is sometimes useful, here the simplest method is to just look at whether the letters are vowels or consonants. Another pitfall is assuming that every question must involve a complex rule, which can lead to wasted time during an exam.

Final Answer:
The only pair that consists entirely of consonants and therefore does not match the vowel pairs is GH.