Difficulty: Easy
Correct Answer: 189
Explanation:
Introduction / Context:
Number classification commonly tests recognition of perfect powers (squares, cubes). A quick square check often isolates the outlier. Here, three items are perfect squares; one is not.
Given Data / Assumptions:
Concept / Approach:
Compute square roots where plausible and verify exactness. If three are n^2 and one is not, the non-square is the odd one out.
Step-by-Step Solution:
121 = 11^2 → perfect square.144 = 12^2 → perfect square.169 = 13^2 → perfect square.189 → 13^2 = 169 and 14^2 = 196, so 189 is between squares; it is not a perfect square.
Verification / Alternative check:
Prime factors: 121 = 11^2; 144 = 2^4 * 3^2; 169 = 13^2; 189 = 3^3 * 7 → not all prime exponents even, confirming it is not a square.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing near-squares with exact squares. Always check exactness, not proximity.
Final Answer:
189
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