Number series – find the next term: 9 8 7 6 1 2 3 4 5 9 8 7 1 2 3 4 5 9 8 7 1 2 3 4 9 8 ? The sequence appears to repeat a block “9 8 7 then 1 to 5” several times.

Introduction / Context:This question tests detection of a repeating composite block in a digit series. Rather than a single monotonic rule, the pattern cycles through a short descending run before jumping to an ascending run, then repeats.

Given Data / Assumptions:

• Visible segment: 9 8 7 6 1 2 3 4 5 | 9 8 7 | 1 2 3 4 5 | 9 8 7 | 1 2 3 4 | 9 8 ?
• Assume consistent repetition of the same two-part block.

Concept / Approach:Identify the repeating block. The natural reading is: (A) a short descending run beginning with 9 8 7 (occasionally a 6 appears in the first long showing), then (B) an ascending run 1 2 3 4 5. After an ascending run ends at 5, the cycle restarts at 9 8 7.

Step-by-Step Solution:

Verification / Alternative check:Scan earlier occurrences: after each finished 1–5 ascent, a new “9 8 7” trio starts. The tail matches the start of that trio.

Why Other Options Are Wrong:

Common Pitfalls:Overfitting the very first stretch (which includes a 6) and missing that later cycles consistently show 9 8 7 → 1 2 3 4 5.

Final Answer:7