Difficulty: Medium
Correct Answer: 44 - 31
Explanation:
Introduction / Context:Pair-difference classification often checks whether differences land on special sets (e.g., perfect squares). A single miss identifies the outlier.
Given Data / Assumptions:
Concept / Approach:Compute the difference of each pair and test for perfect-square status.
Step-by-Step Solution:Calculate each difference.Mark square vs non-square results.Identify the pair whose difference is not square.
Verification / Alternative check:Nearest squares around 13 are 9 and 16; 13 is not square, confirming the exception.
Why Other Options Are Wrong:61−12, 34−30, 25−21: Each yields a perfect square difference and thus belongs together.
Common Pitfalls:Miscomputing 61−12 as 51; the correct result is 49.
Final Answer:44 - 31
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