Evaluate the statement about a NOR gate: “The output of a NOR gate is LOW if any of its inputs is LOW.” Is this statement valid for NOR logic?

Introduction / Context:
NOR is the negation of OR. Understanding when NOR outputs 0 versus 1 is vital when designing active-low logic and combined functions.

Given Data / Assumptions:

• NOR = NOT(OR).
• Inputs may be 0 or 1.

Concept / Approach:
OR outputs 1 when any input is 1. Consequently, NOR outputs 0 when any input is 1, and NOR outputs 1 only when all inputs are 0. The given statement wrongly references any input being LOW (0).

Step-by-Step Solution:
1) If any input = 1, OR = 1, so NOR = 0.2) If all inputs = 0, OR = 0, so NOR = 1.3) Therefore, the claim about “any input LOW” causing LOW output is incorrect.

Verification / Alternative check:
Compare two-input truth tables for OR and NOR to confirm the complement relationship.

Why Other Options Are Wrong:
“Correct” contradicts NOR behavior; restrictions to input count or equality are irrelevant to NOR’s definition.

Common Pitfalls:
Confusing NOR with NAND; mixing up the OR condition (any 1) with the wrong trigger (any 0).

Final Answer:
Incorrect