Logic Behavior — A is LOW or B is LOW (or both) implies X is LOW; only when A and B are both HIGH does X become HIGH. Which 2-input gate follows this rule?

Question

Solve this multiple-choice question and choose the correct option.

Accepted Answer

Introduction: The prompt describes an output that is HIGH exclusively when both inputs are HIGH, and LOW otherwise. Recognizing this verbal truth table is a core skill in digital electronics for mapping behaviors to gate names.Given Data / Assumptions: Inputs: A and B are binary (LOW = 0, HIGH = 1) Output: X is binary X is HIGH only if A = 1 and B = 1 Concept / Approach: The AND function outputs 1 only when all inputs are 1. If any input is 0, the output is 0. This statement precisely matches the verbal rule provided.Step-by-Step Solution: Step 1: Translate text to logic: X = 1 only when A = 1 and B = 1.Step 2: Standard AND truth table: 00 → 0, 01 → 0, 10 → 0, 11 → 1.Step 3: The rule matches the AND truth table exactly. Verification / Alternative check: Compare to OR: OR would output 1 when any input is 1, which contradicts the prompt. XOR outputs 1 when inputs differ, also not matching. NAND outputs 0 only for 11, which is the inverse of the described behavior. Why Other Options Are Wrong: XOR gate: High for unequal inputs, not both high.OR gate: High if any input is high; contradicts rule for single highs.NAND gate: Inverts AND; output would be LOW when both inputs are HIGH. Common Pitfalls: Misreading the phrase "or both are LOW" as an OR description; the key is output LOW in those cases.Confusing NAND with AND due to similar names. Final Answer: AND gate

Logic Behavior — A is LOW or B is LOW (or both) implies X is LOW; only when A and B are both HIGH does X become HIGH. Which 2-input gate follows this rule?

More Questions from Logic Gates

Discussion & Comments