Difficulty: Easy
Correct Answer: Directly proportional to absolute temperature (T)
Explanation:
Introduction / Context:Every resistor generates random thermal noise due to the agitation of charge carriers. Understanding how this noise scales with temperature is essential for low-noise RF and instrumentation design.
Given Data / Assumptions:
Concept / Approach:
Thermal noise power spectral density at the terminals of a matched resistor is kT per hertz. The mean-square noise voltage over bandwidth B is 4kTRB. Hence noise power and voltage grow linearly with absolute temperature T (in kelvin).
Step-by-Step Solution:
Noise spectral density: N0 = kT (W/Hz).Mean square noise voltage: v_n^2 = 4kTRB.Therefore v_n ∝ sqrt(T) and noise power ∝ T.Verification / Alternative check:
Cooling a low-noise amplifier or front-end (e.g., cryogenic LNAs) reduces T and thus reduces noise floor proportionally.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Directly proportional to absolute temperature (T)
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