Difficulty: Easy
Correct Answer: equal volumes of oxygen and acetylene
Explanation:
Introduction / Context:
Flame chemistry in oxy–acetylene welding directly affects weld pool metallurgy and surface appearance. A neutral flame is the default choice for steels and many nonferrous alloys because it neither adds excess carbon nor strips alloying elements by oxidation.
Given Data / Assumptions:
Concept / Approach:
A neutral flame forms when oxygen and acetylene are supplied in roughly equal volumetric proportions at the tip, resulting in complete combustion: C2H2 + O2 (primary) followed by secondary combustion with surrounding oxygen. The visual cue is a well-defined inner cone with no acetylene feather. An oxidizing flame uses excess oxygen (short, sharp inner cone, hissing sound), while a carburizing (reducing) flame uses excess acetylene (long feather beyond inner cone) and can introduce carbon or soot into the weld.
Step-by-Step Solution:
Verification / Alternative check:
Welding handbooks define neutral flame at approximately 1:1 oxygen-to-acetylene ratio by volume at the tip, with allowances for tip size and back pressure.
Why Other Options Are Wrong:
Common Pitfalls:
Judging solely by sound; ignoring the acetylene feather; not compensating for tip size and regulator settings.
Final Answer:
Discussion & Comments