Problems on Ages — “Five years ago, Ashu’s mother was 3 times Ashu’s age. Five years from now she will be twice Ashu’s age. Find Ashu’s present age.”

Difficulty: Medium

Correct Answer: 15 years

Explanation:


Introduction / Context:
This problem mirrors the earlier two-equation pattern with past and future multiplicative age relations. Represent present ages with variables and translate the time-shifted statements into equations to solve cleanly.


Given Data / Assumptions:

  • Let Ashu = x, Mother = y (present ages).
  • Five years ago: y − 5 = 3(x − 5).
  • Five years hence: y + 5 = 2(x + 5).


Concept / Approach:
Convert to present-age equations and solve simultaneously for x.


Step-by-Step Solution:

From past: y − 5 = 3x − 15 ⇒ y = 3x − 10. …(1)From future: y + 5 = 2x + 10 ⇒ y = 2x + 5. …(2)Set equal: 3x − 10 = 2x + 5 ⇒ x = 15.Ashu’s present age = 15 years.


Verification / Alternative check:
Five years ago Ashu 10, Mother 30 ⇒ 30 = 3 * 10 ✓; in five years Ashu 20, Mother 40 ⇒ 40 = 2 * 20 ✓.


Why Other Options Are Wrong:
10/12/20/35 violate at least one of the two time-shifted multiplicative conditions.


Common Pitfalls:
Applying the multiplier to current ages directly; forgetting to shift both ages by the same number of years when moving to past or future.


Final Answer:
15 years

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