Difficulty: Easy
Correct Answer: will increase with the concentration of the growth limiting substrate until it reaches a maximum value
Explanation:
Introduction:
The Monod model is a cornerstone of biochemical engineering and environmental biotechnology. It relates the specific growth rate of microorganisms to the concentration of a single growth-limiting substrate. Understanding the qualitative behavior of μ with respect to substrate concentration helps in designing bioreactors, setting feed strategies, and predicting washout or overload conditions.
Given Data / Assumptions:
Concept / Approach:
The Monod equation is μ = μ_max * S / (K_s + S). As S increases from very low values, μ rises but asymptotically approaches μ_max. This captures saturation behavior that mirrors enzyme kinetics. The relationship is hyperbolic, not linear at high S, and not independent of S in the sub-saturating region.
Step-by-Step Solution:
Step 1: Start with μ = μ_max * S / (K_s + S).Step 2: For S << K_s, μ ≈ (μ_max / K_s) * S, so μ increases approximately linearly with S at low concentrations.Step 3: For S ≈ K_s, μ ≈ μ_max/2, showing the half-saturation point.Step 4: For S >> K_s, μ → μ_max, meaning the rate approaches a maximum and cannot increase further by simply adding more substrate.Step 5: Conclude that the correct qualitative statement is that μ increases with S until a maximum value is reached.
Verification / Alternative check:
Plotting μ versus S using the Monod form yields a rectangular hyperbola that approaches μ_max asymptotically. This is consistent with experimental growth data for many heterotrophs in defined media.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming linearity across all S, confusing μ (specific rate) with overall biomass growth rate, or neglecting that other factors like oxygen transfer or inhibition may cap growth in real reactors even before S reaches saturating values.
Final Answer:
will increase with the concentration of the growth limiting substrate until it reaches a maximum value
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