Rigid-Body Dynamics – Moment of Inertia of a Thin Spherical Shell For a thin spherical shell of mass m and radius r, what is the mass moment of inertia about any diameter?
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Am r^2 / 3
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B2 m r^2 / 3
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C2 m r^2 / 5
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D3 m r^2 / 5
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Em r^2
Answer
Correct Answer: 2 m r^2 / 3
Explanation
Introduction / Context: Standard mass moment of inertia formulas are essential in rotational dynamics. A thin spherical shell concentrates mass at a constant radius, changing its inertia compared with a solid sphere.
Given Data / Assumptions:
- Rigid thin spherical shell (negligible thickness).
- Mass m uniformly distributed over the surface of radius r.
- Axis of rotation: any diameter of the sphere.
Concept / Approach: Known results: Solid sphere about diameter: I = 2 m r^2 / 5. Thin spherical shell about diameter: I = 2 m r^2 / 3. The shell’s mass is farther from the center compared with a solid sphere, hence the larger coefficient.
Step-by-Step Solution: Use standard result for a thin shell: I_diameter = 2 m r^2 / 3. No integration needed in an exam setting because it is a tabulated formula.
Verification / Alternative check: Relative comparison: 2/3 ≈ 0.667 is greater than 2/5 = 0.4, reflecting the mass being distributed at radius r rather than throughout the volume.
Why Other Options Are Wrong: m r^2 / 3: too small; not a standard result. 2 m r^2 / 5: that is for a solid sphere, not a thin shell. 3 m r^2 / 5 and m r^2: do not correspond to any standard spherical model about a diameter.
Common Pitfalls: Mixing up solid vs thin-shell formulas; always recall shell has larger inertia for the same m and r.
Final Answer: 2 m r^2 / 3