In the mixed case alphabet series KlMnO, qRsTu, WxYzA, cDeFg, which of the following terms should come next to maintain both the letter order and the upper and lower case pattern?

Introduction / Context:
This question presents a more visually complex alphabet series that mixes upper case and lower case letters: KlMnO, qRsTu, WxYzA, cDeFg, ?. We have to decide which option continues both the sequence of letters and the pattern of capitalisation. These questions test not only recognition of alphabetic progressions but also attention to formatting details such as letter case, which is especially important in modern reasoning tests where visual patterns are often embedded in text.

Given Data / Assumptions:

• Given terms: KlMnO, qRsTu, WxYzA, cDeFg, ?.• Each term has exactly 5 letters.• Ignoring case, the letters in each term are consecutive segments of the alphabet.• There is a clear alternating pattern in the use of upper and lower case letters.• We must preserve both the sequence of letters and the recurring case pattern.

Concept / Approach:
We handle the problem in two layers. First, we determine the underlying sequence of letters as if everything were in the same case. This reveals how the starting letter of each 5 letter block moves through the alphabet. Second, we analyse the capitalisation pattern across the positions (for example, upper lower upper lower upper) and see how that pattern alternates between successive terms. The correct answer must satisfy both the letter sequence and the case pattern simultaneously.

Step-by-Step Solution:
Step 1: Strip case and examine letter groups: KlMnO → KLMNO, qRsTu → QRSTU, WxYzA → WXYZA, cDeFg → CDEFG.Step 2: Observe that each group is a consecutive run of five letters.Step 3: Find the starting letters: K, Q, W, C.Step 4: Convert to positions: K=11, Q=17, W=23, C=3.Step 5: Differences (forward, with wrap around): 11 → 17: +6, 17 → 23: +6, 23 → 3: +6 (since 23 + 6 = 29 and 29 − 26 = 3).Step 6: Thus the starting letter advances by +6 each time. The next start after C (3) is 3 + 6 = 9, which is I.Step 7: So the next raw letter block should be IJKLM.Step 8: Now examine the case pattern. For KlMnO, positions 1 to 5 have cases: upper, lower, upper, lower, upper (U l U l U).Step 9: For qRsTu, the case pattern is lower, upper, lower, upper, lower (l U l U l).Step 10: For WxYzA, pattern is again U l U l U, and for cDeFg it is l U l U l.Step 11: Thus the pattern alternates between U l U l U and l U l U l. The next term should follow U l U l U again.Step 12: Apply this pattern to IJKLM: I (upper), j (lower), K (upper), l (lower), M (upper), giving IjKlM.

Verification / Alternative check:
Compare each option with the expected letters and case pattern. Only IjKlM uses exactly the letters I, J, K, L, M in the right order and with the case pattern upper, lower, upper, lower, upper. Options iJkLm and hIjKl either start from the wrong letter or reverse the upper and lower case assignments. HiJkL has the wrong starting letter entirely. Therefore, IjKlM is the only choice that satisfies both the alphabetic progression and the alternation of case patterns seen in the series.

Why Other Options Are Wrong:
Option a, iJkLm, starts with a lower case i, which does not match the expected upper case at the first position for this term in the alternation. Option b, HiJkL, uses H as the starting letter rather than I, breaking the +6 rule. Option d, hIjKl, both starts from the wrong letter and applies an inconsistent case pattern. None of these options produce the clean combination of IJKLM with U l U l U capitalisation that the series demands.

Common Pitfalls:
Some candidates focus solely on the letters and ignore case, which leads them to choose an option that may have the right letters but the wrong capitalisation. Others may be distracted by the changing case and miss the simple underlying pattern in the starting letters. The best practice in such mixed format series is to separate the problem into letter sequence and case sequence, solve each independently, and then find the option that satisfies both conditions at once.

Final Answer:
IjKlM