Difficulty: Easy
Correct Answer: both temperature and volume will increase
Explanation:
Introduction / Context:
An isobaric (constant-pressure) process is common in piston–cylinder devices with a sliding weight or regulated outlet. Understanding how temperature and volume respond to heat addition at constant pressure is foundational for analyzing compressors, heaters, and gas turbine components.
Given Data / Assumptions:
Concept / Approach:
At constant pressure, the First law on a per–unit mass basis gives: δq = dh for ideal gases, where h = h(T). Thus heat addition increases enthalpy and therefore temperature. From the ideal-gas relation p * v = R * T at fixed p, any increase in T requires a proportional increase in specific volume v. Hence both T and v rise when heat is supplied isobarically.
Step-by-Step Solution:
Verification / Alternative check:
On a T–v diagram at fixed pressure, isobars slope upward; heating moves the state to higher T and higher v. In practical devices, the piston moves outward while the gas warms, confirming both increases.
Why Other Options Are Wrong:
Only temperature or only volume increases: Inconsistent with p * v = R * T at constant p.No change or temperature decrease: Violates positive cp and heat addition effects for gases.
Common Pitfalls:
Confusing isobaric with isochoric processes. At constant volume, temperature rises but volume does not; at constant pressure, both temperature and volume rise together.
Final Answer:
both temperature and volume will increase
Discussion & Comments