Difficulty: Easy
Correct Answer: all of these
Explanation:
Introduction / Context:
Engineering calculations often require converting standard atmospheric pressure between multiple unit systems. Being fluent with these equivalences avoids mistakes in sizing pumps, compressors, and instrumentation calibrations.
Given Data / Assumptions:
Concept / Approach:
Key exact or conventional values used in engineering: 1 atm ≈ 101325 N/m^2 (Pa) ≈ 1.013 × 10^5 N/m^2. This equals approximately 1.013 bar (since 1 bar = 10^5 Pa) and corresponds to a mercury column of 760 mm under standard conditions. Therefore, the grouped option stating “all of these” is correct. Note that 1.013 × 10^6 N/m^2 would be 10.13 bar, which is not standard atmospheric pressure.
Step-by-Step Solution:
Verification / Alternative check:
Instrument calibration tables and ISO/ISA standards list these same equivalences, validating the consolidated choice.
Why Other Options Are Wrong:
1.013 × 10^6 N/m^2: Ten times larger than 1 atm.
Common Pitfalls:
Mixing bar (10^5 Pa) with Pascal and kiloPascal; remember 1 bar = 100 kPa (exact by definition).
Final Answer:
all of these
Discussion & Comments