Difficulty: Easy
Correct Answer: molecular mass * specific gas constant (R)
Explanation:
Introduction / Context:
Two common forms of the gas constant appear in thermodynamics: R_u, the universal (molar) gas constant with units J/(mol·K), and R, the specific gas constant with units J/(kg·K). Converting between them requires the molar (molecular) mass of the gas.
Given Data / Assumptions:
Concept / Approach:
The relationship is R_u = M * R, where M is the molar mass of the gas and R is its specific gas constant on a per-mass basis. This follows directly from writing the ideal-gas equation either as p * V = n * R_u * T (molar form) or p * v = R * T (specific form) and substituting n = m/M.
Step-by-Step Solution:
Start with p * V = n * R_u * T and n = m / M.Divide by mass m to get p * v = (R_u / M) * T.Identify R = R_u / M → rearrange to R_u = M * R.Therefore, the correct product is molecular mass times specific gas constant.
Verification / Alternative check:
For air: M ≈ 28.97 kg/kmol, R ≈ 0.287 kJ/(kg·K). Product M * R ≈ 28.97 * 0.287 ≈ 8.314 kJ/(kmol·K) = R_u, confirming the relation.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing per-mole and per-mass quantities. Always ensure unit consistency when converting between R and R_u.
Final Answer:
molecular mass * specific gas constant (R)
Discussion & Comments