Combustion stoichiometry check: One kilogram of sulphur (S) reacts with one kilogram of oxygen (O2) to yield two kilograms of sulphur dioxide (SO2). Is this statement correct?

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
Sulphur oxidation is a standard stoichiometric reaction in combustion and gas treatment. Verifying mass ratios builds comfort with balancing reactions and predicting flue-gas composition for desulphurization or sulfuric acid production trains.


Given Data / Assumptions:

  • Reaction considered: S + O2 → SO2 (complete oxidation to dioxide).
  • Atomic masses: S = 32, O = 16.
  • Ideal, complete conversion without side reactions.


Concept / Approach:

Balance by moles: 1 mol S (32 kg/kmol) reacts with 1 mol O2 (32 kg/kmol) to form 1 mol SO2 (64 kg/kmol). Thus, per kilogram basis, 1 kg S needs 1 kg O2 and produces 2 kg SO2. While further oxidation to SO3 can occur in catalytic processes, the primary combustion product without catalyst is SO2.


Step-by-Step Solution:

Write reaction: S + O2 → SO2.Compute masses: 32 + 32 → 64 (kg per kmol basis).Scale per kg: 1 kg S + 1 kg O2 → 2 kg SO2.


Verification / Alternative check:

Mass conservation and standard oxidation supports the same ratio; flue-gas analyzers report SO2 as the primary sulfur oxide absent catalytic conversion.


Why Other Options Are Wrong:

Dependence on excess air or pressure does not change the stoichiometric mass ratio for the ideal reaction.SO3 formation requires specific catalytic conditions; it is not the default product in simple combustion.


Common Pitfalls:

Confusing oxygen atom mass with O2 molecular mass; always use O2 = 32 for combustion stoichiometry.


Final Answer:

True

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