Flue-gas mass per kilogram of fuel – carbon balance method In ultimate analysis calculations, the mass of dry flue gas per kilogram of fuel can be expressed as the ratio of which two masses?

Mechanical Engineering Thermodynamics Difficulty: Medium
Choose an option
  • A
    mass of carbon in 1 kg of fuel to the mass of carbon in 1 kg of flue gas
  • B
    mass of oxygen in 1 kg of flue gas to the mass of oxygen in 1 kg of fuel
  • C
    mass of oxygen in 1 kg of fuel to the mass of oxygen in 1 kg of flue gas
  • D
    mass of carbon in 1 kg of flue gas to the mass of carbon in 1 kg of fuel
  • E
    mass of nitrogen in 1 kg of fuel to the mass of nitrogen in 1 kg of flue gas

Answer

Correct Answer: mass of carbon in 1 kg of fuel to the mass of carbon in 1 kg of flue gas

Explanation

Introduction / Context:Determining the amount of flue gas generated per kilogram of fuel is a common step in combustion calculations. One reliable approach uses a carbon balance, because essentially all fuel carbon appears in the products as CO2 and CO (for complete combustion, almost all as CO2).

Given Data / Assumptions:

  • Dry flue gas basis (water vapour removed) is used.
  • All carbon in the fuel exits in the dry flue gas as CO2 (and possibly CO if incomplete, but measured in analysis).
  • Elemental conservation applies exactly: input carbon equals output carbon.

Concept / Approach:If m_fg is the mass of dry flue gas per kg of fuel, and if (C_fuel) is the mass of carbon in 1 kg of fuel, while (C_per_kg_fg) is the mass of carbon present in 1 kg of dry flue gas (obtainable from gas analysis), then by carbon balance: C_fuel = m_fg * C_per_kg_fg, hence m_fg = C_fuel / C_per_kg_fg.

Step-by-Step Solution:Define C_fuel = mass of C in 1 kg fuel (kg C/kg fuel).From gas analysis, find C_per_kg_fg (kg C/kg dry flue gas).Apply conservation: C_fuel = m_fg * C_per_kg_fg → m_fg = C_fuel / C_per_kg_fg.Recognize that this equals “mass of carbon in 1 kg of fuel” divided by “mass of carbon in 1 kg of flue gas.”

Verification / Alternative check:An equivalent oxygen-balance approach is possible but is more sensitive to incomplete combustion and to moisture; the carbon balance on a dry basis is robust.

Why Other Options Are Wrong:

  • The oxygen-based ratios reverse numerator/denominator and are not generally used in this simple form.
  • Using nitrogen from fuel is inappropriate because fuel-bound nitrogen is small and most nitrogen in products comes from air.
  • Option (d) inverts the correct ratio, yielding m_fg inverse.

Common Pitfalls:Mixing wet and dry gas bases or forgetting that nearly all nitrogen in flue gas originates from the oxidizer (air), not the fuel.

Final Answer:mass of carbon in 1 kg of fuel to the mass of carbon in 1 kg of flue gas

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