Difficulty: Easy
Correct Answer: isentropic
Explanation:
Introduction / Context:
To analyze gas-turbine (Brayton) performance, we adopt an ideal model with simplified, reversible processes. These assumptions enable closed-form relations between temperatures and pressure ratio and a compact expression for thermal efficiency. This question focuses on the assumed character of compression and expansion in that ideal model.
Given Data / Assumptions:
Concept / Approach:
In the ideal Brayton cycle, the compressor and turbine are modeled as adiabatic and reversible, i.e., isentropic. This yields T2/T1 = r_p^((gamma−1)/gamma) for the compressor and T3/T4 = r_p^((gamma−1)/gamma) for the turbine (with r_p the pressure ratio). These relations underpin the well-known efficiency formula eta = 1 − 1/r_p^((gamma−1)/gamma).
Step-by-Step Solution:
Verification / Alternative check:
Real machines are polytropic with efficiencies below 100%; the ideal isentropic benchmark is used to define and compute those efficiencies and to bound performance.
Why Other Options Are Wrong:
Isothermal compression/expansion is not representative for Brayton hardware; “polytropic” describes real behavior, not the ideal assumption; “isobaric” processes apply to the heater/cooler (heat addition/rejection), not the turbomachinery.
Common Pitfalls:
Applying isentropic relations at very high temperatures without accounting for variable properties; misusing absolute vs. gauge pressures when computing r_p.
Final Answer:
isentropic
Discussion & Comments