Entropy change when heat is removed from a gas Consider a closed system of an ideal (perfect) gas. If heat is removed from the gas (i.e., the system rejects heat), is the change in the system's entropy necessarily positive?

Mechanical Engineering Thermodynamics Difficulty: Easy
Choose an option
  • A
    Yes, entropy change is always positive when heat is removed
  • B
    No, entropy change is generally negative when heat is removed at a given temperature
  • C
    It is always zero regardless of process details
  • D
    It depends only on pressure, not on the process path
  • E
    It depends on reversibility; entropy may decrease despite heat removal if generation is small

Answer

Correct Answer: No, entropy change is generally negative when heat is removed at a given temperature

Explanation

Introduction / Context:Entropy quantifies the energy dispersal per unit temperature and sets limits on heat-to-work conversion. This question examines the sign of entropy change when a gas rejects heat. Understanding the distinction between entropy transfer with heat and entropy generation due to irreversibility is crucial for thermodynamics and refrigeration problems.

Given Data / Assumptions:

  • Closed system containing a fixed mass of ideal gas.
  • Heat is removed from the system (Q < 0 for the process considered).
  • Temperature is measured on the Kelvin scale.
  • Process may be reversible or irreversible unless otherwise specified.

Concept / Approach:The entropy change of a system over any process can be written as ΔS_system = ∫(δQ_rev/T) + S_gen, where S_gen ≥ 0 accounts for irreversibilities. For a reversible path at temperature T, rejecting heat (δQ_rev < 0) gives a negative contribution to ΔS. Only if irreversibilities are present and large enough can the positive S_gen outweigh the negative heat-term and make ΔS nonnegative.

Step-by-Step Solution:State the relation: ΔS_system = ∫(δQ_rev/T) + S_gen.For heat removal at representative temperature T: ∫(δQ_rev/T) is negative.For a reversible cooling step: S_gen = 0, hence ΔS_system < 0.For an irreversible cooling step: ΔS_system = negative quantity + S_gen; sign depends on magnitude of S_gen.Therefore, the blanket statement “entropy change is positive when heat is removed” is incorrect.

Verification / Alternative check:Cooling water or gas in a reversible heat exchanger reduces the fluid’s entropy, while the surroundings gain entropy by |Q|/T_surroundings. The total entropy of the universe increases or stays the same, but the system’s entropy typically decreases upon heat removal.

Why Other Options Are Wrong:Option A claims always positive—contradicted by reversible cooling. Option C claims always zero—false except for special contrived paths. Option D ignores the path dependence of heat and the role of T. Option E is partially insightful but still does not make the original unconditional statement true; the correct evaluation of the stem is “No”.

Common Pitfalls:Confusing system entropy change with total entropy generation; assuming “heat out” must increase entropy due to the second law (it does not for the system; it does for the surroundings or the total).

Final Answer:No, entropy change is generally negative when heat is removed at a given temperature

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