Effect of axial compression (push) on dimensions:\nA rectangular bar of length l, width b, and thickness t is subjected to a compressive axial load P. Which dimensional change is correct (considering Poisson’s effect)?

Difficulty: Easy

Correct Answer: length decreases, width and thickness increase

Explanation:


Introduction / Context:
Poisson’s effect couples axial and lateral strains. Under compression (push), a bar shortens axially and tends to bulge laterally, a behavior crucial for fit tolerances, buckling, and contact problems.


Given Data / Assumptions:

  • Axial compressive load P along the length.
  • Linear elastic material with positive Poisson’s ratio.
  • Small deformations and uniform stress state.


Concept / Approach:
Axial compressive strain is negative, while lateral strains are positive and proportional to ν times the axial strain (with opposite sign). Hence, length decreases; width and thickness increase.


Step-by-Step Solution:

Axial strain: epsilon_long = -σ / E < 0Lateral strain: epsilon_lat = -ν * epsilon_long > 0Therefore: Δl < 0; Δb > 0; Δt > 0


Verification / Alternative check:
Cylindrical compression tests and compression of rubber blocks visibly show shortening with lateral bulging, confirming the sign pattern of strains.


Why Other Options Are Wrong:

  • All dimensions increasing/decreasing contradicts Poisson’s coupling.
  • Length increases (option C) is opposite to compression.
  • Length unchanged (option E) is unrealistic under finite compressive stress.


Common Pitfalls:
Confusing tension and compression effects; ignoring small but significant lateral expansions that influence fits and clearances.


Final Answer:
length decreases, width and thickness increase

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