Elastic constants relationship:\nFor a material with Poisson’s ratio ν = 0.4, what is the ratio of shear modulus to Young’s modulus (G/E)?

Difficulty: Easy

Correct Answer: 5/14

Explanation:


Introduction / Context:
In isotropic linear elasticity, the independent constants E (Young’s modulus), G (shear modulus), and ν (Poisson’s ratio) are linked. Converting between them is routine in strength of materials and finite element modeling.


Given Data / Assumptions:

  • Isotropic, homogeneous material.
  • Poisson’s ratio ν = 0.4.
  • Standard elastic relation G = E / [2 * (1 + ν)].


Concept / Approach:
Use the canonical relationship connecting E, G, and ν. Substituting ν directly gives the ratio without needing absolute values of E or G.


Step-by-Step Solution:

G = E / [2 * (1 + ν)]With ν = 0.4 ⇒ 1 + ν = 1.4G/E = 1 / [2 * 1.4] = 1 / 2.81 / 2.8 = 0.357142… = 5 / 14


Verification / Alternative check:
Sanity check: For ν between 0 and 0.5, G/E should lie between 1/3 and 1/2.8; 5/14 ≈ 0.357 fits the expected range.


Why Other Options Are Wrong:

  • 5/7, 7/5, 14/5 are greater than 1, impossible for G/E with ν = 0.4.
  • 2/5 = 0.4 does not match the exact relation for ν = 0.4.


Common Pitfalls:
Forgetting the 2 in the denominator; confusing G/E with E/G; using an incorrect ν value range that yields nonphysical ratios.


Final Answer:
5/14

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