Mohr’s circle basics: The radius of Mohr’s circle equals which combination of the two principal stresses?

Difficulty: Easy

Correct Answer: Half the difference of the two principal stresses

Explanation:


Introduction / Context:
Mohr’s circle graphically represents plane stress transformation. Knowing the center and radius allows immediate computation of principal stresses and maximum shear stress.



Given Data / Assumptions:

  • Principal stresses σ1 and σ2 are real values (plane stress state).
  • Standard plotting: σ-axis horizontal, τ-axis vertical.
  • Positive shear convention consistent with Mohr’s construction.


Concept / Approach:
The circle’s center is at C = (σ1 + σ2)/2 on the σ-axis, and the radius is R = (σ1 − σ2)/2. The maximum in-plane shear equals this radius.



Step-by-Step Solution:

Plot points A(σ1, 0) and B(σ2, 0) on the σ-axis.Center C is the midpoint of AB → (σ1 + σ2)/2.Radius R is half the length of AB → (σ1 − σ2)/2.


Verification / Alternative check:
General stress components (σx, σy, τxy) reduce to principal form by rotation; analytical solutions give σ1,2 = (σx + σy)/2 ± √[ ((σx − σy)/2)^2 + τxy^2 ], where the radical equals the radius R.



Why Other Options Are Wrong:
Sum or half-sum describe the center, not the radius.Full difference is twice the radius.Product has no direct geometric meaning in Mohr’s circle radius.



Common Pitfalls:
Mixing center and radius formulas; sign mistakes in τ that reflect points across the σ-axis.



Final Answer:

Half the difference of the two principal stresses

More Questions from Strength of Materials

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion