Difficulty: Easy
Correct Answer: Shear stress
Explanation:
Introduction / Context:
Shafts transmit torque in machines (motors, gearboxes, rotors). The dominant stress under pure torsion for circular shafts is shear, which defines the torsional strength and angle of twist.
Given Data / Assumptions:
Concept / Approach:
In circular shafts, warping is negligible and cross-sections remain plane. The shear stress varies linearly with radius: tau(r) = T * r / J where T is torque and J is polar second moment of area. Normal stresses (tension/compression) arise only if bending or axial loads are present.
Step-by-Step Solution:
Verification / Alternative check:
Mohr’s circle for pure shear shows principal normal stresses ±tau at 45°, but the applied stress state on the cross-section is shear.
Why Other Options Are Wrong:
Tension/Compression/Bending are not produced by pure torque in a circular shaft.Hydrostatic stress requires equal normal stresses in all directions, unrelated to torsion.
Common Pitfalls:
Confusing principal normal stresses at 45° with applied shear on the cross-section; applying noncircular-shaft concepts where warping matters.
Final Answer:
Shear stress
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