Difficulty: Easy
Correct Answer: It decreases the exit velocity due to kinetic energy loss
Explanation:
Introduction / Context:
Nozzle friction converts part of the available enthalpy drop into entropy rather than directed kinetic energy. Appreciating this effect is crucial for predicting jet speed and turbine work.
Given Data / Assumptions:
Concept / Approach:
In an ideal nozzle, the isentropic enthalpy drop fully converts to kinetic energy: V^2/2 = Δh_isentropic. With friction, the actual kinetic energy equals η_nozzle * Δh_isentropic, where 0 < η_nozzle < 1. Thus, exit velocity is lower.
Step-by-Step Solution:
Write V_actual^2 / 2 = η_nozzle * Δh_isentropic.For fixed inlet and exit pressures, friction raises entropy and reduces effective Δh to kinetic energy.Therefore, V_actual < V_isentropic; exit velocity decreases.
Verification / Alternative check:
Measured nozzle coefficients (velocity coefficient < 1) quantify this reduction; test data show lower exit Mach numbers and speeds than ideal predictions.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming choked flow guarantees ideal velocity; choking fixes Mach at the throat, not exit losses.
Final Answer:
It decreases the exit velocity due to kinetic energy loss
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